How does… any of this even work. I am atm trying to set the term A’(x) equal ro zero ro get orher results to continue math but i can’t figure out how to do so.
Does the context of this mean that you can move -6x^-2 to the other side?
Because then you get 6x=6x^-2
Which would mean x=x^-2
Which should mean that x=1 because 1 to any power will be 1 so 1^1=1^-2
I’m not entirely sure on the context so I don’t even know if you are trying to find x, but I’m pretty sure it’s 1
I can only really figure out about 10-20% of what’s being said here.
Also I still have another 74 questions of my own that I need to be doing so I’d rather not think about this any more than I need to
It’s for over a long period of time, but being suddenly given about a hundred questions all at once and being told “yeah go work on these” is a little daunting
i don’t quite know what the question is but i’m gonna assume it’s
6x - 6x^(-2) = 0, solve for x
u can just multiply both sides by x^2
6x^3 - 6 = 0
6(x^3 - 1) = 0
x^3 - 1 = 0
x = 1 is the only solution