still 2? 
incorrect! it is (sqrt(2)e^(2iπ^2))^2
Not for long it won’t be
no it isn’t
e^(2iπ^2)=1 by Euler’s formula
sqrt(2)*1=sqrt(2) by multiplicative identity
sqrt(2)^2=2 by cancellation
therefore (sqrt(2)e^(2iπ^2))^2 = 2, which yeah dream got right but i just thought his answer wasnt fancy enough which is why it is incorrect
eulers formula is e^(2ipi) = 1 not e^(2ipi^2) = 1 
idk me big stupid durrr
(i thought it was e^(iπΘ) where theta is the angle)
