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  1. There are 12 people in a luck 5 fishing party. It takes around 30 seconds to one minute to catch a fish. There is a 1/2000 chance that one of them fishes out a sunken normally. The luck 5 is splashed, and the chance of a sunken being caught is increased by x%. The pot lasts for one hour. At the end of the hour all of the players have collectively fished out a total of 12 sunkens. Find the exact percentage increase (x%) the luck 5 potion provides, and provide the new chance of catching a sunken under the influence of the luck potion in fraction form (1/x chance).

  2. There are a total of 8 different sunken pieces that all have an equal chance of being caught out of that 1/2000 chance normally. I want a sunken warrior chestplate. What are the chances of me catching a sw chest under the influence of luck 5 for an hour?

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90% as per the wiki
(to be honest I completely forgot how to do that sort of problem lol. All I remember is that it was really tedious to do and required a lot of memorization)

So out of an 1/2000 chance, you have a further 1/8 chance of getting the prefered drop. That gives you a base chance of 1/16000 (.00625%) of reeling in a Sunken Warrior Chestplate.

Assuming the 90% increase in drop chance is correct, that would mean with Luck V you would have a .011875% chance of getting your Sunken Warrior Chestplate per reel.

Lets take the worst case scenario of a minute per reel, that would mean you would have 60 reels before losing the luck effect. This means that the probability of you not reeling in your sunken warrior chestplate would be (1-.011875)^60. To get that to be the probability of you getting your sunken, we can subtract 1 by all of it (1-(1-.011875)^60)

That leaves us with approximately .71% chance of you getting your sunken warrior chestplate. for the best case scenario, it would go up to 1.415% chance.

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ummm whats 2+2

4

log4x+1(7) + log9x(7) = 0

billions must luck party…

this is fake, sunken items are unobtainable and can only be given by vetex

Actually 900% wiki is wrong

Currently doing this.

Lets isolate the logs to each side. log_9x (7) = -log_4x+1 (7)

update: i gave up :pensive:

Well if it is wrong please tell me what the correct percentage increase it is then, so that I may correct my equation.

I just said it’s +900%

Also known as x10

The question’s also bad because it’s not an independent probability problem since after any multiple of 3000 fish caught you’re guaranteed a sunken and we wouldn’t know how close the players are to their pity in the party

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geometry?

True, but we can ignore it since the amount of reels is relatively small.

We can’t because we literally have 0 clue how close the 12 people are to their pity

ran it through chatgpt

Since the luck 5 potion increases the chance of catching a sunken by x%, we can calculate the new chance of catching a sunken per person per fish:

  • (1/120) + (x/100)(1/120) = 1/2000

Now, let’s solve for x:

  • (1/120) + (x/100)(1/120) = 1/2000
  • 1 + (x/100) = 1/16,000
  • x/100 = 1/16,000 - 1
  • x/100 = (1 - 16,000)/16,000
  • x/100 = -15,999/16,000
  • x = (15,999/16,000) * 100
  • x ≈ 99.994%

Therefore, the luck 5 potion provides an exact percentage increase of approximately 99.994% (x ≈ 99.994%).

To find the new chance of catching a sunken under the influence of the luck potion in fraction form (1/x chance):

  • 1/x = 1/(1/120 + (99.994/100)(1/120))
  • 1/x = 1/(1/120 + 0.99994/120)
  • 1/x = 1/(1.99994/120)
  • 1/x = 120/1.99994
  • 1/x ≈ 60.001

Therefore, the new chance of catching a sunken under the influence of the luck 5 potion is approximately 1 in 60.001 (1/x ≈ 1/60.001 chance).

nah bro it’s not 1/60 chance

also shouldn’t luck factor in the amount of items obtainable from fishing or do u not care abt that bec u already have the percents

Doing this again with the correct percentage.

1/16000 base chance, bumped up to 1/1600 with the +900% luck boost.
blah blah blah math stuff I already explained, you get a 3.69% chance for the low estimate and 7.2% for the high.

Don’t trust chat gpt

It’s 1/200